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SOLVED: What is the hybridization state of carbon in carbocation, carbanion and free radical?
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![In which radical odd electron is in pure orbital \\[N{O_2},{\\text{ }}Cl{O_2},{\\text{ }}C{H_3},{\\text{ }}Cl{F_3}\\]?](https://www.vedantu.com/question-sets/b72a22a3-4aef-4967-b710-7a72b409f37a3158202302521036403.png "In which radical odd electron is in pure orbital \\[N{O_2},{\\text{ }}Cl{O_2},{\\text{ }}C{H_3},{\\text{ }}Cl{F_3}\\]?")
In which radical odd electron is in pure orbital \\[N{O_2},{\\text{ }}Cl{O_2},{\\text{ }}C{H_3},{\\text{ }}Cl{F_3}\\]?
Why is the hybridization of this carbon sp2 and not sp3? Google states that radicals DO count towards hybridization. So, there are technically 4 electron domains around the Carbon, why isn't the
